What is the tangent of f(x)=x^2-9,(4,7) ?

The tangent of f(x)=x^2-9,(4,7) is y=8x-25

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tangent of f(x)=x^2-9,(4,7)

tangent of

f (x) = x^{2} - 9, (4, 7)

y = 8 x - 25

Solution steps

Find the slope of

f (x) = x^{2} - 9 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 9

(4, 7) : m = 8

Find the line with slope m=

8

and passing through

(4, 7) : y = 8 x - 25

y = 8 x - 25

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What is the tangent of f(x)=x^2-9,(4,7) ?
The tangent of f(x)=x^2-9,(4,7) is y=8x-25