What is area e^x,e^{4x},[0,1] ?

The answer to area e^x,e^{4x},[0,1] is -e+1+(e^4-1)/4

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area e^x,e^{4x},[0,1]

area

e^{x}, e^{4 x}, [0, 1]

- e + 1 + \frac{e ^{4} - 1}{4}

Decimal Notation

11.68125 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} e^{x} - e^{4 x} d x

Solve

\int_{0}^{1} e^{x} - e^{4 x} d x : - e + 1 + \frac{e ^{4} - 1}{4}

The area is:

= - e + 1 + \frac{e ^{4} - 1}{4}

x^{3} + 2 x

\int \frac{2}{e ^{4 x}} d x

\frac{d}{d x} (\frac{2 x}{1 - cot ( x )})

\int - sin^{3} (x) cos^{2} (x) d x

\int \frac{y ^{2} - 144}{y} d y

What is area e^x,e^{4x},[0,1] ?
The answer to area e^x,e^{4x},[0,1] is -e+1+(e^4-1)/4