What is the derivative of sin(2x-2pi) ?

The derivative of sin(2x-2pi) is cos(2x)*2

What is the first derivative of sin(2x-2pi) ?

The first derivative of sin(2x-2pi) is cos(2x)*2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (sin (2 x - 2 π))

cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (sin (2 x - 2 π))

Simplify

sin (2 x - 2 π) : sin (2 x)

= \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= cos (2 x) \cdot 2

\int \frac{1}{x ^{2} + 2 x + 5} d x

\frac{\partial}{\partial x} (ln (x^{6} + 1) + y^{2})

\frac{d}{d x} (\frac{5}{12} (3 + 5) x^{3})

x \to - \infty lim (x^{0})

\frac{\partial}{\partial x} (e^{y} - x e^{x})

What is the derivative of sin(2x-2pi) ?
The derivative of sin(2x-2pi) is cos(2x)*2
What is the first derivative of sin(2x-2pi) ?
The first derivative of sin(2x-2pi) is cos(2x)*2