What is the solution for derivative of 9x^2y^2=1 ?

The solution for derivative of 9x^2y^2=1 is y=(sqrt(x+c_{1)})/(3x),y=-(sqrt(x+c_{1)})/(3x)

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derivative of 9x^2y^2=1

\frac{d}{d x} 9 x^{2} y^{2} = 1

y = \frac{x + c _{1}}{3 x}, y = - \frac{x + c _{1}}{3 x}

Solution steps

\frac{d}{d x} (9 x^{2} y^{2}) = 1

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

9 x^{2} y^{2} = \int 1 d x

\int 1 d x = x + c_{1}

9 x^{2} y^{2} = x + c_{1}

Isolate

y : y = \frac{x + c _{1}}{3 x}, y = - \frac{x + c _{1}}{3 x}

y = \frac{x + c _{1}}{3 x}, y = - \frac{x + c _{1}}{3 x}

\int (tan (x) + sec (x)) d x

\frac{\partial}{\partial y} (\frac{e ^{x}}{1 + e ^{y}})

f (x) = 3

\frac{d}{d θ} ((csc (θ) + cot (θ))^{- 1})

\frac{d y}{d x} + e^{x + y} = 0

What is the solution for derivative of 9x^2y^2=1 ?
The solution for derivative of 9x^2y^2=1 is y=(sqrt(x+c_{1)})/(3x),y=-(sqrt(x+c_{1)})/(3x)