What is the derivative of (x^2/y) ?

The derivative of (x^2/y) is (2xy-\frac{dy)/(dx)x^2}{y^2}

What is the first derivative of (x^2/y) ?

The first derivative of (x^2/y) is (2xy-\frac{dy)/(dx)x^2}{y^2}

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\frac{d}{d x} (\frac{x ^{2}}{y})

\frac{2 x y - \frac{d y}{d x} x ^{2}}{y ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{y})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) y - \frac{d y}{d x} x ^{2}}{y ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{2 x y - \frac{d y}{d x} x ^{2}}{y ^{2}}

\int \frac{1}{1 - u ^{2}} d u

\frac{x - x ^{2}}{x} - 2 cot (x)

t \frac{d y}{d t} - y = y t

\frac{\partial}{\partial x} (e^{- 7 x} cos (7 π t))

What is the derivative of (x^2/y) ?
The derivative of (x^2/y) is (2xy-\frac{dy)/(dx)x^2}{y^2}
What is the first derivative of (x^2/y) ?
The first derivative of (x^2/y) is (2xy-\frac{dy)/(dx)x^2}{y^2}