What is the tangent of y=2x^3,(2,16) ?

The tangent of y=2x^3,(2,16) is y=24x-32

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tangent of y=2x^3,(2,16)

tangent of

y = 2 x^{3}, (2, 16)

y = 24 x - 32

Solution steps

Find the slope of

y = 2 x^{3} : \frac{d y}{d x} = 6 x^{2}

Compute the slope of

y = 2 x^{3}

(2, 16) : m = 24

Find the line with slope m=

24

and passing through

(2, 16) : y = 24 x - 32

y = 24 x - 32

\int \frac{1}{x x + 1} d x

y = (\frac{x}{1 + x})^{5}

\frac{d}{d x} (2 x \cdot e^{x^{2}})

x \to 25 lim (x - 5)

\frac{d}{d x} (\frac{x}{3 + e ^{x}})