What is area f(x)=sin(x),-(2pi)/3 , pi/3 ?

The answer to area f(x)=sin(x),-(2pi)/3 , pi/3 is 2

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area f(x)=sin(x),-(2pi)/3 , pi/3

area

f (x) = sin (x), - \frac{2 π}{3}, \frac{π}{3}

2

Solution steps

Apply the area formula:

\int_{- \frac{2 π}{3}}^{\frac{π}{3}} ∣ sin (x) ∣ d x

Solve

\int_{- \frac{2 π}{3}}^{\frac{π}{3}} ∣ sin (x) ∣ d x : 2

The area is:

= 2

\int \frac{6 x}{( x ^{2} + 3 ) ^{2}} d x

3 - x^{2}, 11 - 6 x

\int 8 x cos (x) d x

\int \frac{3 x + 2}{x ^{2} - 11} d x

x \to 0 lim (\frac{sin ( 3 x )}{x})

What is area f(x)=sin(x),-(2pi)/3 , pi/3 ?
The answer to area f(x)=sin(x),-(2pi)/3 , pi/3 is 2