What is the derivative of y=2x^3-3x^2 ?

The derivative of y=2x^3-3x^2 is 6x^2-6x

What is the first derivative of y=2x^3-3x^2 ?

The first derivative of y=2x^3-3x^2 is 6x^2-6x

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derivative of

y = 2 x^{3} - 3 x^{2}

6 x^{2} - 6 x

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

= 6 x^{2} - 6 x

y^{^{''}} + 2 y = 0, y (0) = 1, y (1) = 0

y = arccot (t)

y^{^{''}} + 200 y^{^{'}} + 10 y = 100

\frac{d}{d x} (\frac{2 x}{x + 7})

\frac{d}{d x} (\frac{x ^{2}}{x + 3})

What is the derivative of y=2x^3-3x^2 ?
The derivative of y=2x^3-3x^2 is 6x^2-6x
What is the first derivative of y=2x^3-3x^2 ?
The first derivative of y=2x^3-3x^2 is 6x^2-6x