What is the (1/((1-x)^2))^' ?

The (1/((1-x)^2))^' is 2/((1-x)^3)

What is the first (1/((1-x)^2))^' ?

The first (1/((1-x)^2))^' is 2/((1-x)^3)

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(\frac{1}{( 1 - x ) ^{2}})^{^{'}}

\frac{2}{( 1 - x ) ^{3}}

Solution steps

(\frac{1}{( 1 - x ) ^{2}})^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= ((1 - x)^{- 2})^{^{'}}

Apply the chain rule:

- \frac{2}{( 1 - x ) ^{3}} (1 - x)^{'}

= - \frac{2}{( 1 - x ) ^{3}} (1 - x)^{'}

(1 - x)^{'} = - 1

= - \frac{2}{( 1 - x ) ^{3}} (- 1)

Simplify

= \frac{2}{( 1 - x ) ^{3}}

y = \frac{1}{4 x ^{2}}, y = x, y = \frac{x}{10}

\frac{d}{d x} (\frac{x - 1}{x ^{2} + 4})

x^{2} \frac{d y}{d x} = x y + 3 y^{2}

50 x^{2} e^{- x} + 8

\frac{d}{d u} (\frac{u}{v})