What is the derivative of 7/(2x) ?

The derivative of 7/(2x) is -7/(2x^2)

What is the first derivative of 7/(2x) ?

The first derivative of 7/(2x) is -7/(2x^2)

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\frac{d}{d x} (\frac{7}{2 x})

- \frac{7}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{7}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{7}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{7}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{7}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{7}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{7}{2 x ^{2}}

= - \frac{7}{2 x ^{2}}

x \to - 1 lim (4 x^{3} + x^{2} + 2 x + 1)

\frac{d y}{d x} = y x^{9} sin (x^{10})

\frac{d}{d x} (\frac{1}{7 x})

\int (x^{2} - 1) (2 x + 1) d x

\int cos^{6} (2 x) d x

What is the derivative of 7/(2x) ?
The derivative of 7/(2x) is -7/(2x^2)
What is the first derivative of 7/(2x) ?
The first derivative of 7/(2x) is -7/(2x^2)