What is the solution for (y+1)y^'=xy-y ?

The solution for (y+1)y^'=xy-y is y=\W(1/(e^{(-x^2+2x-c_{1))/2}})

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(y+1)y^'=xy-y

(y + 1) y^{^{'}} = x y - y

y = W (\frac{1}{e ^{\frac{- x ^{2} + 2 x - c _{1}}{2}}})

Solution steps

(y + 1) y^{'} (x) = x y - y

Solve separable ODE:

y = W (\frac{1}{e ^{\frac{- x ^{2} + 2 x - c _{1}}{2}}})

y = W (\frac{1}{e ^{\frac{- x ^{2} + 2 x - c _{1}}{2}}})

e^{a x^{3}}

\frac{d y}{d x} = e^{2 y + 8 x}

\frac{d}{d x} (sin^{3} (x^{2} + 7))

\frac{1}{2 s ^{2} + 8 s + 10}

\int \frac{1}{2} (x + y) e^{- x - y} d x

What is the solution for (y+1)y^'=xy-y ?
The solution for (y+1)y^'=xy-y is y=\W(1/(e^{(-x^2+2x-c_{1))/2}})