What is the derivative of (21\sqrt[3]{x}/(x^2-1)) ?

The derivative of (21\sqrt[3]{x}/(x^2-1)) is (7(x^2-6\sqrt[3]{x}x^{5/3}-1))/(x^{2/3)(x^2-1)^2}

What is the first derivative of (21\sqrt[3]{x}/(x^2-1)) ?

The first derivative of (21\sqrt[3]{x}/(x^2-1)) is (7(x^2-6\sqrt[3]{x}x^{5/3}-1))/(x^{2/3)(x^2-1)^2}

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Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d x} (x^{2} - 1) = 2 x

Simplify

\frac{d}{d x} (e^{- 3 x} sin (3 x))

- 3 x^{4}

f (x) = \frac{e ^{x - 3}}{x - 2}

\int \frac{1}{z ^{2} - z} d z

\int_{1}^{7} \frac{1}{9 + ( x + 2 ) ^{2}} d x

What is the derivative of (21\sqrt[3]{x}/(x^2-1)) ?
The derivative of (21\sqrt[3]{x}/(x^2-1)) is (7(x^2-6\sqrt[3]{x}x^{5/3}-1))/(x^{2/3)(x^2-1)^2}
What is the first derivative of (21\sqrt[3]{x}/(x^2-1)) ?
The first derivative of (21\sqrt[3]{x}/(x^2-1)) is (7(x^2-6\sqrt[3]{x}x^{5/3}-1))/(x^{2/3)(x^2-1)^2}