What is the limit as x approaches 0 of (sin(4x^2))/x ?

The limit as x approaches 0 of (sin(4x^2))/x is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (sin(4x^2))/x

x \to 0 lim (\frac{sin ( 4 x ^{2} )}{x})

0

Solution steps

x \to 0 lim (\frac{sin ( 4 x ^{2} )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{cos ( 4 x ^{2} ) \cdot 8 x}{1})

= x \to 0 lim (\frac{cos ( 4 x ^{2} ) \cdot 8 x}{1})

Plug in the value

x = 0

= \frac{cos ( 4 \cdot 0 ^{2} ) \cdot 8 \cdot 0}{1}

Simplify

\frac{cos ( 4 \cdot 0 ^{2} ) \cdot 8 \cdot 0}{1} : 0

= 0

\frac{\partial}{\partial x} (x \cdot y^{2} \cdot z^{3})

(4 x - 3)^{5} (3 - x^{3})^{2}

y^{^{''}} - 16 y^{^{'}} + 64 y = t^{- 2} e^{8 t}

3 x^{2} + 5 y = 0

\int_{1}^{1000} \frac{5}{x ^{3}} d x

What is the limit as x approaches 0 of (sin(4x^2))/x ?
The limit as x approaches 0 of (sin(4x^2))/x is 0