What is the integral of 1/(sqrt((1+x^2))) ?

The integral of 1/(sqrt((1+x^2))) is ln|sqrt(x^2+1)+x|+C

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integral of 1/(sqrt((1+x^2)))

\int \frac{1}{( 1 + x ^{2} )} d x

ln x^{2} + 1 + x + C

Solution steps

\int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = ln x^{2} + 1 + x

= ln x^{2} + 1 + x

Add a constant to the solution

= ln x^{2} + 1 + x + C

\frac{d}{d x} (3 x^{4} - 3 x^{3} - 2)

x \to 1 - lim (3 x)

\frac{d}{d x} (\frac{π}{2 x})

\frac{d}{d x} (cos ((1 - x^{2})^{2}))

y = x^{2}, y = 4 - x^{2}

What is the integral of 1/(sqrt((1+x^2))) ?
The integral of 1/(sqrt((1+x^2))) is ln|sqrt(x^2+1)+x|+C