What is the integral of ((ln(x)))/(x^2) ?

The integral of ((ln(x)))/(x^2) is -(ln(x))/x-1/x+C

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integral of ((ln(x)))/(x^2)

\int \frac{( ln ( x ) )}{x ^{2}} d x

- \frac{ln ( x )}{x} - \frac{1}{x} + C

Solution steps

\int \frac{ln ( x )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

= - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

\int - \frac{1}{x ^{2}} d x = \frac{1}{x}

= - \frac{ln ( x )}{x} - \frac{1}{x}

Add a constant to the solution

= - \frac{ln ( x )}{x} - \frac{1}{x} + C

\frac{\partial}{\partial x} (x^{8} y^{6} - x^{7} y^{5})

x \to \infty lim (7^{- x})

\frac{\partial}{\partial x} (\frac{x + 6 y}{y ^{2} + 3 x ^{2}})

\int_{1}^{4} \frac{2}{x ^{2} + 4 x + 4} d x

3 t - e^{- 3 t}

What is the integral of ((ln(x)))/(x^2) ?
The integral of ((ln(x)))/(x^2) is -(ln(x))/x-1/x+C