What is (\partial)/(\partial x)(cos(8y-2x)) ?

The answer to (\partial)/(\partial x)(cos(8y-2x)) is 2sin(8y-2x)

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(\partial)/(\partial x)(cos(8y-2x))

\frac{\partial}{\partial x} (cos (8 y - 2 x))

2 sin (8 y - 2 x)

Solution steps

\frac{\partial}{\partial x} (cos (8 y - 2 x))

Treat

y

as a constant

Apply the chain rule:

- sin (8 y - 2 x) \frac{\partial}{\partial x} (8 y - 2 x)

= - sin (8 y - 2 x) \frac{\partial}{\partial x} (8 y - 2 x)

\frac{\partial}{\partial x} (8 y - 2 x) = - 2

= - sin (8 y - 2 x) (- 2)

Simplify

= 2 sin (8 y - 2 x)

\frac{\partial}{\partial y} (\frac{x}{x ^{2} + y ^{2}})

\int 9 x e^{- x} d x

\int_{0}^{1} x^{3} - 3 x^{2} + 2 x d x

y = x^{2} - 5 x + 5

\int x^{2} (6 - x) d x

What is (\partial)/(\partial x)(cos(8y-2x)) ?
The answer to (\partial)/(\partial x)(cos(8y-2x)) is 2sin(8y-2x)