What is the derivative of (2x^2+7)^5 ?

The derivative of (2x^2+7)^5 is 20x(2x^2+7)^4

What is the first derivative of (2x^2+7)^5 ?

The first derivative of (2x^2+7)^5 is 20x(2x^2+7)^4

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derivative of

(2 x^{2} + 7)^{5}

20 x (2 x^{2} + 7)^{4}

Solution steps

\frac{d}{d x} ((2 x^{2} + 7)^{5})

Apply the chain rule:

5 (2 x^{2} + 7)^{4} \frac{d}{d x} (2 x^{2} + 7)

= 5 (2 x^{2} + 7)^{4} \frac{d}{d x} (2 x^{2} + 7)

\frac{d}{d x} (2 x^{2} + 7) = 4 x

= 5 (2 x^{2} + 7)^{4} \cdot 4 x

Simplify

= 20 x (2 x^{2} + 7)^{4}

\frac{\partial}{\partial x} (2 e^{x y} ln (x^{2} + y^{2}))

\frac{d}{d x} (\frac{2 - 3 x}{4})

\frac{d}{d v} (x^{v})

\int \frac{1}{x ^{2} - 1} d x

f (x) = x + 8, at x = 8

What is the derivative of (2x^2+7)^5 ?
The derivative of (2x^2+7)^5 is 20x(2x^2+7)^4
What is the first derivative of (2x^2+7)^5 ?
The first derivative of (2x^2+7)^5 is 20x(2x^2+7)^4