What is the derivative of f(-5)=x^3-2 ?

The derivative of f(-5)=x^3-2 is 3x^2

What is the first derivative of f(-5)=x^3-2 ?

The first derivative of f(-5)=x^3-2 is 3x^2

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derivative of

f (- 5) = x^{3} - 2

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2) = 0

= 3 x^{2} - 0

Simplify

= 3 x^{2}

\int_{0}^{\frac{π}{2}} sin^{2} (4 x) d x

\frac{d}{d x} (n x)

\int \frac{( x + 1 ) ( x - 1 )}{x} d x

\int x sin (9 x) d x

3 y^{^{''}} = 8 e^{- 4 t}

What is the derivative of f(-5)=x^3-2 ?
The derivative of f(-5)=x^3-2 is 3x^2
What is the first derivative of f(-5)=x^3-2 ?
The first derivative of f(-5)=x^3-2 is 3x^2