What is the integral of (32r^7)/(sqrt(2-r^8)) ?

The integral of (32r^7)/(sqrt(2-r^8)) is (32r^7dr)/(sqrt(2-r^8))x+C

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integral of (32r^7)/(sqrt(2-r^8))

\int \frac{32 r ^{7} d r}{2 - r ^{8}} d x

\frac{32 r ^{7} d r}{2 - r ^{8}} x + C

Solution steps

\int \frac{32 r ^{7} d r}{2 - r ^{8}} d x

Integral of a constant:

\int a d x = a x

= \frac{32 r ^{7} d r}{2 - r ^{8}} x

Add a constant to the solution

= \frac{32 r ^{7} d r}{2 - r ^{8}} x + C

\frac{d}{d x} (\frac{x}{2 x + 5})

\frac{d}{d x} ((1 + x)^{3})

\int_{1}^{3} \frac{x ^{2} + 7}{4 x - x ^{2}} d x

\frac{\partial}{\partial x} (2 x y e^{- x^{2} - y^{2}})

\frac{d}{d x} (6 sec (x) tan (x))

What is the integral of (32r^7)/(sqrt(2-r^8)) ?
The integral of (32r^7)/(sqrt(2-r^8)) is (32r^7dr)/(sqrt(2-r^8))x+C