What is (\partial)/(\partial x)(x^2cos(x)y) ?

The answer to (\partial)/(\partial x)(x^2cos(x)y) is y(2xcos(x)-x^2sin(x))

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(\partial)/(\partial x)(x^2cos(x)y)

\frac{\partial}{\partial x} (x^{2} cos (x) y)

y (2 x cos (x) - x^{2} sin (x))

Solution steps

\frac{\partial}{\partial x} (x^{2} cos (x) y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (x^{2} cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = cos (x)

= y (\frac{\partial}{\partial x} (x^{2}) cos (x) + \frac{\partial}{\partial x} (cos (x)) x^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= y (2 x cos (x) + (- sin (x)) x^{2})

Simplify

= y (2 x cos (x) - x^{2} sin (x))

\int e^{- θ} cos (2 θ) d θ

\int (2 x - 9) e^{2 x} d x

\frac{d}{d x} (- \frac{3 y}{3 x + 2 y})

\frac{d}{d x} (\frac{1}{( 3 - x ) ^{2}})

cos (k \cdot t)

What is (\partial)/(\partial x)(x^2cos(x)y) ?
The answer to (\partial)/(\partial x)(x^2cos(x)y) is y(2xcos(x)-x^2sin(x))