What is the solution for ((x^2+1)dy)/(dx)=-y^2-1 ?

The solution for ((x^2+1)dy)/(dx)=-y^2-1 is y=tan(-arctan(x)-c_{1})

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((x^2+1)dy)/(dx)=-y^2-1

\frac{( x ^{2} + 1 ) d y}{d x} = - y^{2} - 1

y = tan (- arctan (x) - c_{1})

Solution steps

\frac{( x ^{2} + 1 ) d y}{d x} = - y^{2} - 1

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What is the solution for ((x^2+1)dy)/(dx)=-y^2-1 ?
The solution for ((x^2+1)dy)/(dx)=-y^2-1 is y=tan(-arctan(x)-c_{1})