What is the integral of (15)/(x^2+1) ?

The integral of (15)/(x^2+1) is 15arctan(x)+C

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integral of (15)/(x^2+1)

\int \frac{15}{x ^{2} + 1} d x

15 arctan (x) + C

Solution steps

\int \frac{15}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 15 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= 15 arctan (x)

Add a constant to the solution

= 15 arctan (x) + C

e^{17 x}

f (x) = x ln (x)

\frac{d}{d x} (x e^{2 x^{2} - 4 x})

y = x^{3} - 2 x + 2, (4, 58)

What is the integral of (15)/(x^2+1) ?
The integral of (15)/(x^2+1) is 15arctan(x)+C