What is the integral of (x/(sqrt(x^2-2))) ?

The integral of (x/(sqrt(x^2-2))) is sqrt(x^2-2)+C

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integral of (x/(sqrt(x^2-2)))

\int (\frac{x}{x ^{2} - 2}) d x

x^{2} - 2 + C

Solution steps

\int \frac{x}{x ^{2} - 2} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= \frac{1}{2} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = x^{2} - 2

= \frac{1}{2} \cdot 2 (x^{2} - 2)^{\frac{1}{2}}

Simplify

\frac{1}{2} \cdot 2 (x^{2} - 2)^{\frac{1}{2}} : x^{2} - 2

= x^{2} - 2

Add a constant to the solution

= x^{2} - 2 + C

10 cos (8 t) + 14 sin (8 t)

x \to 1 lim (2 x^{\frac{3}{2}} - 3 x^{2})

\frac{d}{d x} (7 x^{2} + 8 x)

f (x) = 3 x^{2} + 2 x, at p (- 1, 5)

What is the integral of (x/(sqrt(x^2-2))) ?
The integral of (x/(sqrt(x^2-2))) is sqrt(x^2-2)+C