What is the limit as x approaches 0 of 2/(x^3+x) ?

The limit as x approaches 0 of 2/(x^3+x) is diverges

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limit as x approaches 0 of 2/(x^3+x)

x \to 0 lim (\frac{2}{x ^{3} + x})

diverges

Solution steps

x \to 0 lim (\frac{2}{x ^{3} + x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{2}{x ^{3} + x}) = \infty

x \to 0 - lim (\frac{2}{x ^{3} + x}) = - \infty

= diverges

y = π

\frac{\partial}{\partial x} (x^{3} y^{4} + x^{4} y^{3})

\frac{\partial}{\partial x} (e^{\frac{6}{x}})

\frac{d}{d t} (e^{- t} (2 cos (\frac{t}{2}) - 3 sin (\frac{t}{2})))

(x^{2} + 16) \frac{d y}{d x} + x y - 4 x = 0

What is the limit as x approaches 0 of 2/(x^3+x) ?
The limit as x approaches 0 of 2/(x^3+x) is diverges