What is the derivative of 0.41sqrt(x) ?

The derivative of 0.41sqrt(x) is (0.205)/(sqrt(x))

What is the first derivative of 0.41sqrt(x) ?

The first derivative of 0.41sqrt(x) is (0.205)/(sqrt(x))

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\frac{d}{d x} (0.41 x)

\frac{0.205}{x}

Solution steps

\frac{d}{d x} (0.41 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.41 \frac{d}{d x} (x)

Apply radical rule:

a = a^{\frac{1}{2}}

= 0.41 \frac{d}{d x} (x^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 0.41 \cdot \frac{1}{2} x^{\frac{1}{2} - 1}

Simplify

0.41 \cdot \frac{1}{2} x^{\frac{1}{2} - 1} : \frac{0.205}{x}

= \frac{0.205}{x}

\frac{\partial}{\partial x} (1)

\int x^{3} e^{x^{2}} d x

\int - x sin (x) cos (x) d x

\int \frac{1}{3} sin (x - 3) + e^{x + 3} + x^{- 3} d x

x \to 0 lim ((2 + x)^{3} - 8)

What is the derivative of 0.41sqrt(x) ?
The derivative of 0.41sqrt(x) is (0.205)/(sqrt(x))
What is the first derivative of 0.41sqrt(x) ?
The first derivative of 0.41sqrt(x) is (0.205)/(sqrt(x))