What is the g(x)=((ln(x-x^2)))/8+\sqrt[3]{x} ?

The g(x)=((ln(x-x^2)))/8+\sqrt[3]{x} is

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g(x)=((ln(x-x^2)))/8+\sqrt[3]{x}

Domain : 0 < x < 1

Range : f (x) \leq 0.70022 \dots

Intercepts : None

Asymptotes : Vertical x = 0, x = 1

Extreme Points : Maximum (0.77526 \dots, 0.70022 \dots)

Interval Notation

Domain : (0, 1)

Range : (- \infty, 0.70022 \dots]

Solution steps

Domain of

Range of

Axis interception points of

None

Asymptotes of

Vertical

: x = 0, x = 1

Extreme Points of

Maximum

(0.77526 \dots, 0.70022 \dots)

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12 x^{2}

(t - 6.8) sin (6.2 t)

What is the g(x)=((ln(x-x^2)))/8+\sqrt[3]{x} ?
The g(x)=((ln(x-x^2)))/8+\sqrt[3]{x} is