What is integral from a to b of f(x) ?

The answer to integral from a to b of f(x) is (f(b^2-a^2))/2

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integral from a to b of f(x)

\int_{a}^{b} f (x) d x

\frac{f ( b ^{2} - a ^{2} )}{2}

Solution steps

\int_{a}^{b} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{a}^{b} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{a}^{b}

= f [\frac{x ^{2}}{2}]_{a}^{b}

Compute the boundaries:

\frac{b ^{2}}{2} - \frac{a ^{2}}{2}

= f (\frac{b ^{2}}{2} - \frac{a ^{2}}{2})

Simplify

= \frac{f ( b ^{2} - a ^{2} )}{2}

(ln (\frac{x}{4}))^{^{'}}

\int 2 x (2 - x) d x

3^{2^{x^{2}}}

x \to 0 lim (\frac{sin ( x ^{7} )}{x})

x \to - 2 + lim (\frac{- 1}{x ^{2} - 4})

What is integral from a to b of f(x) ?
The answer to integral from a to b of f(x) is (f(b^2-a^2))/2