What is the integral of cos(m)x ?

The integral of cos(m)x is 1/2 x^2cos(m)+C

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integral of cos(m)x

\int cos (m) x d x

\frac{1}{2} x^{2} cos (m) + C

Solution steps

\int cos (m) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= cos (m) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= cos (m) \frac{x ^{2}}{2}

Simplify

cos (m) \frac{x ^{2}}{2} : \frac{1}{2} x^{2} cos (m)

= \frac{1}{2} x^{2} cos (m)

Add a constant to the solution

= \frac{1}{2} x^{2} cos (m) + C

\frac{d ^{2}}{d x ^{2}} ((x^{2} + 8)^{9})

f (x) =, 5 + 4 x - 3 x^{2} at x

\int 7 x^{3} (x - 1)^{- 4} d x

y = \frac{a - x}{a + x}

\frac{d y}{d x} - \frac{y}{x} = \frac{x}{y}