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Popular >

derivative of f(x)=ln(sqrt(x)+9)

Solution

derivative of

f (x) = ln (x + 9)

Solution

\frac{1}{2 x ( x + 9 )}

Solution steps

\frac{d}{d x} (ln (x + 9))

Apply the chain rule:

\frac{1}{x + 9} \frac{d}{d x} (x + 9)

= \frac{1}{x + 9} \frac{d}{d x} (x + 9)

\frac{d}{d x} (x + 9) = \frac{1}{2 x}

= \frac{1}{x + 9} \cdot \frac{1}{2 x}

Simplify

\frac{1}{x + 9} \cdot \frac{1}{2 x} : \frac{1}{2 x ( x + 9 )}

= \frac{1}{2 x ( x + 9 )}

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\int_{1}^{10} \frac{13}{x ^{3}} d x

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tangent of y=3x^2+4x+4,(1,1)tangent of

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Frequently Asked Questions (FAQ)

What is the derivative of f(x)=ln(sqrt(x)+9) ?
The derivative of f(x)=ln(sqrt(x)+9) is 1/(2sqrt(x)(\sqrt{x)+9)}
What is the first derivative of f(x)=ln(sqrt(x)+9) ?
The first derivative of f(x)=ln(sqrt(x)+9) is 1/(2sqrt(x)(\sqrt{x)+9)}