What is the tangent of 2sqrt(x)+1,\at x= 1/4 ?

The tangent of 2sqrt(x)+1,\at x= 1/4 is y=2x+3/2

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tangent of 2sqrt(x)+1,\at x= 1/4

tangent of

2 x + 1, at x = \frac{1}{4}

y = 2 x + \frac{3}{2}

Solution steps

Find the tangent point:

(\frac{1}{4}, 2)

Find the slope of

y = 2 x + 1 : \frac{d y}{d x} = \frac{1}{x}

Compute the slope of

y = 2 x + 1

x = \frac{1}{4} : m = 2

Find the line with slope m=

2

and passing through

(\frac{1}{4}, 2) : y = 2 x + \frac{3}{2}

y = 2 x + \frac{3}{2}

n = 1 \sum \infty e^{- n} n!

f (x) = 8^{x}

x \to 8 - lim (\frac{2}{x - 8})

y^{^{''}} + 25 y = sec (5 t)

x^{9} e^{x}

What is the tangent of 2sqrt(x)+1,\at x= 1/4 ?
The tangent of 2sqrt(x)+1,\at x= 1/4 is y=2x+3/2