What is the first derivative of 9e^x ?

The first derivative of 9e^x is 9e^x

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derivative of 9e^x

derivative of

9 e^{x}

9 e^{x}

Solution steps

\frac{d}{d x} (9 e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{x})

Apply the common derivative:

\frac{d}{d x} (e^{x}) = e^{x}

= 9 e^{x}

y (X) = \frac{1}{2 cos ^{2} ( X )}

y = 4 x ln (x) + (3^{x}) - (x^{3})

\int \frac{1}{( 256 + x ^{2} ) ^{\frac{3}{2}}} d x

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\int e^{x} ln (x) d x