What is the integral of x*e^{1-x} ?

The integral of x*e^{1-x} is -e^{1-x}x-e^{1-x}+C

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integral of x*e^{1-x}

\int x \cdot e^{1 - x} d x

- e^{1 - x} x - e^{1 - x} + C

Solution steps

\int x e^{1 - x} d x

Apply Integration By Parts

: - e^{1 - x} x - \int - e^{1 - x} d x

= - e^{1 - x} x - \int - e^{1 - x} d x

\int - e^{1 - x} d x = e^{1 - x}

= - e^{1 - x} x - e^{1 - x}

Add a constant to the solution

= - e^{1 - x} x - e^{1 - x} + C

(2 x - 5)^{4} (8 x^{2} - 5)^{- 3}

\frac{\partial}{\partial y} (y e^{- x y})

\frac{d}{d x} (ln (\frac{e ^{x}}{1 + e ^{x}}))

\frac{\partial}{\partial x} (ln ((cos (x) y)^{z}))

x \to 3 lim (3 x + 7)

What is the integral of x*e^{1-x} ?
The integral of x*e^{1-x} is -e^{1-x}x-e^{1-x}+C