What is the tangent of f(x)=3x^2-5x+7,(-1,15) ?

The tangent of f(x)=3x^2-5x+7,(-1,15) is y=-11x+4

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tangent of f(x)=3x^2-5x+7,(-1,15)

tangent of

f (x) = 3 x^{2} - 5 x + 7, (- 1, 15)

y = - 11 x + 4

Solution steps

Find the slope of

f (x) = 3 x^{2} - 5 x + 7 : \frac{df ( x )}{d x} = 6 x - 5

Compute the slope of

f (x) = 3 x^{2} - 5 x + 7

(- 1, 15) : m = - 11

Find the line with slope m=

- 11

and passing through

(- 1, 15) : y = - 11 x + 4

y = - 11 x + 4

\int 3 x^{2} + 2 d x

\int_{2}^{\infty} \frac{8}{x ^{3}} d x

\frac{1}{x - 1}

\int \frac{10}{x} + \frac{2}{x ^{2}} + \frac{7}{x ^{3}} d x

\int 1 + \frac{1}{4 x} d x

What is the tangent of f(x)=3x^2-5x+7,(-1,15) ?
The tangent of f(x)=3x^2-5x+7,(-1,15) is y=-11x+4