What is the derivative of 2t^2-3t-1 ?

The derivative of 2t^2-3t-1 is 4t-3

What is the first derivative of 2t^2-3t-1 ?

The first derivative of 2t^2-3t-1 is 4t-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

2 t^{2} - 3 t - 1

4 t - 3

Solution steps

\frac{d}{d t} (2 t^{2} - 3 t - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 t^{2}) - \frac{d}{d t} (3 t) - \frac{d}{d t} (1)

\frac{d}{d t} (2 t^{2}) = 4 t

\frac{d}{d t} (3 t) = 3

\frac{d}{d t} (1) = 0

= 4 t - 3 - 0

Simplify

= 4 t - 3

\int \frac{1}{x ^{2} + 2 ^{2}} d x

\frac{1}{( 4 x + 1 ) ^{4}}

4 e^{3 x} (3 cos (4 x) - 4 sin (4 x))

x \to 3 - lim (\frac{x - 2}{x ^{2} - 9})

\frac{d}{d x} (arccsc (- 3 x))

What is the derivative of 2t^2-3t-1 ?
The derivative of 2t^2-3t-1 is 4t-3
What is the first derivative of 2t^2-3t-1 ?
The first derivative of 2t^2-3t-1 is 4t-3