What is the derivative of (e/(16))^x ?

The derivative of (e/(16))^x is (1-4ln(2))(e/(16))^x

What is the first derivative of (e/(16))^x ?

The first derivative of (e/(16))^x is (1-4ln(2))(e/(16))^x

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derivative of

(\frac{e}{16})^{x}

(1 - 4 ln (2)) (\frac{e}{16})^{x}

Solution steps

\frac{d}{d x} ((\frac{e}{16})^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= (\frac{e}{16})^{x} ln (\frac{e}{16})

Simplify

ln (\frac{e}{16}) : - 4 ln (2) + 1

= (1 - 4 ln (2)) (\frac{e}{16})^{x}

\int_{0}^{\frac{1}{2}} y^{2} (8 y) d y

y = (x^{2} - 1)

f (x) = 5 + 4 x^{2} - 2 x^{3}, at x = a

x \to \infty lim (- x + 2)

\int_{0}^{π} 3 sin^{2} (4 x) d x

What is the derivative of (e/(16))^x ?
The derivative of (e/(16))^x is (1-4ln(2))(e/(16))^x
What is the first derivative of (e/(16))^x ?
The first derivative of (e/(16))^x is (1-4ln(2))(e/(16))^x