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Popular >

y^'=(x-1)e^x

Solution

y^{^{'}} = (x - 1) e^{x}

Solution

y = e^{x} x - 2 e^{x} + c_{1}

Solution steps

y^{'} (x) = (x - 1) e^{x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (x - 1) e^{x} d x

\int (x - 1) e^{x} d x = e^{x} x - 2 e^{x} + c_{1}

y = e^{x} x - 2 e^{x} + c_{1}

Popular Examples

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integral of (cos(x)+1/2 x)

\int (cos (x) + \frac{1}{2} x) d x

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g (t) = \frac{t - t}{t ^{\frac{1}{6}}}

(dy}{dx}-y=\frac{e^x)/y

\frac{d y}{d x} - y = \frac{e ^{x}}{y}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x-1)e^x ?
The solution for y^'=(x-1)e^x is y=e^xx-2e^x+c_{1}