What is the derivative of e^4+ln(8) ?

The derivative of e^4+ln(8) is 0

What is the first derivative of e^4+ln(8) ?

The first derivative of e^4+ln(8) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (e^{4} + ln (8))

0

Solution steps

\frac{d}{d x} (e^{4} + ln (8))

e^{4} + ln (8) = e^{4} + 3 ln (2)

= \frac{d}{d x} (e^{4} + 3 ln (2))

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int e^{3 x + 4} d x

x \to 2 - lim (- 2)

y = x + 3, y = \frac{1}{2} x + 3

10 y^{^{''}} - y^{^{'}} - 3 y = 0

\frac{\partial}{\partial x} (5 x^{2} + 5 y^{2})

What is the derivative of e^4+ln(8) ?
The derivative of e^4+ln(8) is 0
What is the first derivative of e^4+ln(8) ?
The first derivative of e^4+ln(8) is 0