What is implicit x^2-4xy+y^2=4 ?

The answer to implicit x^2-4xy+y^2=4 is (dy)/(dx)=(-x+2y)/(y-2x)

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implicit x^2-4xy+y^2=4

implicit derivative

x^{2} - 4 x y + y^{2} = 4

\frac{d y}{d x} = \frac{- x + 2 y}{y - 2 x}

Solution steps

x^{2} - 4 x y + y^{2} = 4

Treat

y

y (x)

Differentiate both sides:

2 x - 4 (y + x \frac{d y}{d x}) + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- x + 2 y}{y - 2 x}

\frac{d y}{d x} = \frac{- x + 2 y}{y - 2 x}

\int (3 x - 1)^{2} d x

\int cos (8 x) d x

f (x) = e^{x} x

\int \frac{x ^{2} - 36}{x ^{3}} d x

y^{^{''}} - 8 y^{^{'}} + 16 y = 0, y (0) = 3, y^{^{'}} (0) = 11

What is implicit x^2-4xy+y^2=4 ?
The answer to implicit x^2-4xy+y^2=4 is (dy)/(dx)=(-x+2y)/(y-2x)