What is (\partial)/(\partial t)(zy^2(t+1)) ?

The answer to (\partial)/(\partial t)(zy^2(t+1)) is zy^2

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(\partial)/(\partial t)(zy^2(t+1))

\frac{\partial}{\partial t} (z y^{2} (t + 1))

z y^{2}

Solution steps

\frac{\partial}{\partial t} (z y^{2} (t + 1))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z y^{2} \frac{\partial}{\partial t} (t + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z y^{2} (\frac{\partial}{\partial t} (t) + \frac{\partial}{\partial t} (1))

\frac{\partial}{\partial t} (t) = 1

\frac{\partial}{\partial t} (1) = 0

= z y^{2} (1 + 0)

Simplify

= z y^{2}

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What is (\partial)/(\partial t)(zy^2(t+1)) ?
The answer to (\partial)/(\partial t)(zy^2(t+1)) is zy^2