What is the derivative of 5x+(400/x) ?

The derivative of 5x+(400/x) is 5-(400)/(x^2)

What is the first derivative of 5x+(400/x) ?

The first derivative of 5x+(400/x) is 5-(400)/(x^2)

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\frac{d}{d x} (5 x + \frac{400}{x})

5 - \frac{400}{x ^{2}}

Solution steps

\frac{d}{d x} (5 x + \frac{400}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x) + \frac{d}{d x} (\frac{400}{x})

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (\frac{400}{x}) = - \frac{400}{x ^{2}}

= 5 - \frac{400}{x ^{2}}

7 y^{^{'}} = y^{2}

f (x) = x e^{3 x^{2} + 1}

\int \frac{1}{( y + 1 ) ( y - 2 )} d y

\frac{\partial}{\partial x} (e^{2 x - y})

f (x) = x^{2} + sin (x)

What is the derivative of 5x+(400/x) ?
The derivative of 5x+(400/x) is 5-(400)/(x^2)
What is the first derivative of 5x+(400/x) ?
The first derivative of 5x+(400/x) is 5-(400)/(x^2)