What is the d/(du)(arctan(u)) ?

The d/(du)(arctan(u)) is 1/(u^2+1)

What is the first d/(du)(arctan(u)) ?

The first d/(du)(arctan(u)) is 1/(u^2+1)

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\frac{d}{d u} (arctan (u))

\frac{1}{u ^{2} + 1}

Solution steps

\frac{d}{d u} (arctan (u))

Apply the common derivative:

\frac{d}{d u} (arctan (u)) = \frac{1}{u ^{2} + 1}

= \frac{1}{u ^{2} + 1}

\int x^{2} - 3 x d x

x \to \frac{π}{6} lim (tan (x))

\frac{\partial}{\partial x} (x^{2} y + y)

\frac{d}{d x} (lo g_{e} (x + 1))

(10 - x) y^{2} = x^{3}, (2, 1)