What is the integral of (x^3)/(64) ?

The integral of (x^3)/(64) is (x^4)/(256)+C

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integral of (x^3)/(64)

\int \frac{x ^{3}}{64} d x

\frac{x ^{4}}{256} + C

Solution steps

\int \frac{x ^{3}}{64} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{64} \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= \frac{1}{64} \cdot \frac{x ^{4}}{4}

Simplify

\frac{1}{64} \cdot \frac{x ^{4}}{4} : \frac{x ^{4}}{256}

= \frac{x ^{4}}{256}

Add a constant to the solution

= \frac{x ^{4}}{256} + C

\int (x^{2} - x + 3) d x

\int \frac{2 x}{x ^{2} + y ^{4}} d x

f (x) = \frac{1}{2 x} x^{9}

(- 1, 7), (3, - 1)

x \to 0 lim (\frac{arccos ( 1 - x )}{x})

What is the integral of (x^3)/(64) ?
The integral of (x^3)/(64) is (x^4)/(256)+C