What is the integral of (sqrt(x)+6)/(\sqrt[3]{x)} ?

The integral of (sqrt(x)+6)/(\sqrt[3]{x)} is 6/7 x^{7/6}+9x^{2/3}+C

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integral of (sqrt(x)+6)/(\sqrt[3]{x)}

\frac{6}{7} x^{\frac{7}{6}} + 9 x^{\frac{2}{3}} + C

Solution steps

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{6}{7} x^{\frac{7}{6}} + 9 x^{\frac{2}{3}}

Add a constant to the solution

= \frac{6}{7} x^{\frac{7}{6}} + 9 x^{\frac{2}{3}} + C

\frac{\partial}{\partial x} (sin (3 x) cos (2 y))

\int (sin (x))^{\frac{1}{3}} cos (x) d x

\int_{6}^{13} ln (x - 6) d x

x \to 0 lim (25)

\frac{d}{d x} (arctan (10 x))

What is the integral of (sqrt(x)+6)/(\sqrt[3]{x)} ?
The integral of (sqrt(x)+6)/(\sqrt[3]{x)} is 6/7 x^{7/6}+9x^{2/3}+C