What is the solution for y^{''}-4y^'+3y=0,y(0)=1,y^'(0)=3 ?

The solution for y^{''}-4y^'+3y=0,y(0)=1,y^'(0)=3 is y=e^{3t}

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y^{''}-4y^'+3y=0,y(0)=1,y^'(0)=3

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = 1, y^{^{'}} (0) = 3

y = e^{3 t}

Solution steps

y^{''} (t) - 4 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = e^{3 t}

y = e^{3 t}

x \to 1 lim (e^{x^{2} - 4 x + 1})

\int sin (in x) d x

\int_{- 1}^{0} 1

\int e^{\frac{x}{y}} d x

x \to 0 - lim (\frac{8}{x} - \frac{8}{∣ x ∣})

What is the solution for y^{''}-4y^'+3y=0,y(0)=1,y^'(0)=3 ?
The solution for y^{''}-4y^'+3y=0,y(0)=1,y^'(0)=3 is y=e^{3t}