What is the integral of arccos(y) ?

The integral of arccos(y) is yarccos(y)-sqrt(1-y^2)+C

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integral of arccos(y)

\int arccos (y) d y

y arccos (y) - 1 - y^{2} + C

Solution steps

\int arccos (y) d y

Apply Integration By Parts

: y arccos (y) - \int - \frac{y}{1 - y ^{2}} d y

= y arccos (y) - \int - \frac{y}{1 - y ^{2}} d y

\int - \frac{y}{1 - y ^{2}} d y = 1 - y^{2}

= y arccos (y) - 1 - y^{2}

Add a constant to the solution

= y arccos (y) - 1 - y^{2} + C

\int_{- 2}^{3} 2 x^{2} + 5 d x

x \to - 7 lim (\frac{1}{x + 7})

\frac{d}{d x} (cot^{3} (π - x))

x \to - 3 lim (\frac{1}{x - 1})

(- 2, 3), (2, - 2)

What is the integral of arccos(y) ?
The integral of arccos(y) is yarccos(y)-sqrt(1-y^2)+C