What is the integral of 7\sqrt[6]{x^5} ?

The integral of 7\sqrt[6]{x^5} is 42/11 x^{11/6}+C

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integral of 7\sqrt[6]{x^5}

\frac{42}{11} x^{\frac{11}{6}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 7 \cdot \int x^{\frac{5}{6}} d x

Apply the Power Rule

: \frac{6}{11} x^{\frac{11}{6}}

= 7 \cdot \frac{6}{11} x^{\frac{11}{6}}

Simplify

7 \cdot \frac{6}{11} x^{\frac{11}{6}} : \frac{42}{11} x^{\frac{11}{6}}

= \frac{42}{11} x^{\frac{11}{6}}

Add a constant to the solution

= \frac{42}{11} x^{\frac{11}{6}} + C

\frac{d}{d x} (ln (cos (x)))

\int \frac{tan ^{2} ( x )}{sec ^{5} ( x )} d x

\int \frac{w}{16 - w ^{2}} d w

\frac{d}{d x} (\frac{x}{x ^{2} + 7})

x \to 0 lim (7 cot^{4} (3 x))

What is the integral of 7\sqrt[6]{x^5} ?
The integral of 7\sqrt[6]{x^5} is 42/11 x^{11/6}+C