What is the solution for derivative of (dy/(dx))=1 ?

The solution for derivative of (dy/(dx))=1 is y=(x^2)/2+c_{1}x+c_{2}

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derivative of (dy/(dx))=1

\frac{d}{d x} (\frac{d y}{d x}) = 1

y = \frac{x ^{2}}{2} + c_{1} x + c_{2}

Solution steps

\frac{d ^{2} y}{d x ^{2}} = 1

Solve

y^{''} (x) = 1 : y^{'} (x) = x + c_{1}

Solve

y^{'} (x) = x + c_{1} : y = \frac{x ^{2}}{2} + c_{1} x + c_{2}

y = \frac{x ^{2}}{2} + c_{1} x + c_{2}

\int \frac{( 3 x - 2 ) ^{2} - ( 3 x + 2 ) ^{2}}{x ^{2}} d x

\frac{d y}{d x} = sin (x) y + e^{x}

y = x^{1 - x}

f (x) = \frac{1}{( 1 + x ^{2} )}

\frac{d}{d x} (4 - \frac{20}{x ^{3}} + \frac{3}{x ^{5}})

What is the solution for derivative of (dy/(dx))=1 ?
The solution for derivative of (dy/(dx))=1 is y=(x^2)/2+c_{1}x+c_{2}