What is the solution for (dy}{dx}=\frac{(x^2-y))/x ?

The solution for (dy}{dx}=\frac{(x^2-y))/x is y=(x^2)/3+(c_{1})/x

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(dy}{dx}=\frac{(x^2-y))/x

\frac{d y}{d x} = \frac{( x ^{2} - y )}{x}

y = \frac{x ^{2}}{3} + \frac{c _{1}}{x}

Solution steps

\frac{d y}{d x} = \frac{( x ^{2} - y )}{x}

Solve linear ODE:

y = \frac{x ^{2}}{3} + \frac{c _{1}}{x}

y = \frac{x ^{2}}{3} + \frac{c _{1}}{x}

\int x + 2 x d x d x

x \to 0 + lim (x^{2} - x - ln (x))

\int \frac{x ^{3} - 2 x - 2}{x ^{4} + 2 x ^{3} + 3 x ^{2}} d x

\frac{d}{d x} (x^{\frac{4}{5}} (x - 6)^{2})

\frac{d}{d x} (1 + cot^{2} (x))

What is the solution for (dy}{dx}=\frac{(x^2-y))/x ?
The solution for (dy}{dx}=\frac{(x^2-y))/x is y=(x^2)/3+(c_{1})/x