What is area x=6y^2,x=4+2y^2 ?

The answer to area x=6y^2,x=4+2y^2 is No Solution

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area x=6y^2,x=4+2y^2

area

x = 6 y^{2}, x = 4 + 2 y^{2}

No Solution

Solution steps

Isolate

y

for

x = 6 y^{2} : y = \frac{x}{6}, y = - \frac{x}{6}

Isolate

y

for

x = 4 + 2 y^{2} : y = \frac{x - 4}{2}, y = - \frac{x - 4}{2}

f_{1} (x) = \frac{x}{6}

f_{2} (x) = - \frac{x}{6}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{6} = - \frac{x}{6} : x = 0

\frac{x}{6} = \frac{x - 4}{2} : x = 6

\frac{x}{6} = - \frac{x - 4}{2} :

No Solution for

x \in R

- \frac{x}{6} = \frac{x - 4}{2} :

No Solution for

x \in R

- \frac{x}{6} = - \frac{x - 4}{2} : x = 6

\frac{x - 4}{2} = - \frac{x - 4}{2} : x = 4

Curves not bounded

= No Solution

f (x) = x (x^{6} - 1), at x = 1

\int e^{x} \cdot cos (3 x) d x

\int \frac{6 x ^{2} - 15 x + 22}{( x + 3 ) ( x ^{2} + 2 ) ^{2}} d x

y = \frac{1}{x}, (4, \frac{1}{2})

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{3 t}

What is area x=6y^2,x=4+2y^2 ?
The answer to area x=6y^2,x=4+2y^2 is No Solution