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Popular >

derivative of 2acos(2x-2bsin(2x))

Solution

\frac{d}{d x} (2 a cos (2 x) - 2 b sin (2 x))

Solution

- 4 a sin (2 x) - 4 b cos (2 x)

Solution steps

\frac{d}{d x} (2 a cos (2 x) - 2 b sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 a cos (2 x)) - \frac{d}{d x} (2 b sin (2 x))

\frac{d}{d x} (2 a cos (2 x)) = - 4 a sin (2 x)

\frac{d}{d x} (2 b sin (2 x)) = 4 b cos (2 x)

= - 4 a sin (2 x) - 4 b cos (2 x)

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derivative of f(x)=(x^2-2sqrt(x))/x derivative of

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\int_{0}^{c} 10 e^{2 x} d x

Frequently Asked Questions (FAQ)

What is the derivative of 2acos(2x-2bsin(2x)) ?
The derivative of 2acos(2x-2bsin(2x)) is -4asin(2x)-4bcos(2x)
What is the first derivative of 2acos(2x-2bsin(2x)) ?
The first derivative of 2acos(2x-2bsin(2x)) is -4asin(2x)-4bcos(2x)